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(B) The reaction between the chloride and $AgNO_3$ is: $Ag^{+} + Cl^{-} ightarrow AgCl_{(s)}$.Number of moles of $AgNO_3 = 	ext{Molarity} 	imes

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$XCl_2$

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(B) The reaction between the chloride and $AgNO_3$ is: $Ag^{+} + Cl^{-} ightarrow AgCl_{(s)}$.Number of moles of $AgNO_3 = 	ext{Molarity} 	imes 	ext{Volume (in L)} = 0.1 \ M 	imes 0.01 \ L = 10^{-3} \ mol$.Number of moles of the chloride solution $= 0.05 \ M 	imes 0.01 \ L = 0.5 	imes 10^{-3} \ mol$.Let the formula of the chloride be $XCl_n$. The number of moles of $Cl^{-}$ ions provided by the solution is $n 	imes (0.5 	imes 10^{-3}) \ mol$.According to the stoichiometry of the reaction,moles of $Cl^{-}$ must equal moles of $Ag^{+}$:$n 	imes 0.5 	imes 10^{-3} = 10^{-3}$.Solving for $n$: $n = \frac{10^{-3}}{0.5 	imes 10^{-3}} = 2$.Therefore,the formula of the chloride is $XCl_2$.

In an experiment,it was shown that $10 \ mL$ of a $0.05 \ M$ solution of a chloride required $10 \ mL$ of a $0.1 \ M$ solution of $AgNO_3$. Which of the following will be the formula of the chloride ($X$ stands for the symbol of the element other than chlorine)?

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