(C) Standard resistance,$S=4 \ \Omega$.At $t_1=0^{\circ} C$,the balancing length is $l_1=50 \ cm$.The resistance of the coil $X$ is given by $R_1 = \f

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) Standard resistance,$S=4 \ \Omega$.At $t_1=0^{\circ} C$,the balancing length is $l_1=50 \ cm$.The resistance of the coil $X$ is given by $R_1 = \frac{l_1}{100-l_1} \times S$.$R_1 = \frac{50}{100-50} \times 4 = \frac{50}{50} \times 4 = 4 \ \Omega$.At $t_2=100^{\circ} C$,the balancing length is $l_2=60 \ cm$.The resistance of the coil $X$ is $R_2 = \frac{l_2}{100-l_2} \times S$.$R_2 = \frac{60}{100-60} \times 4 = \frac{60}{40} \times 4 = 6 \ \Omega$.The temperature coefficient of resistance $\alpha$ is given by $\alpha = \frac{R_2 - R_1}{R_1(t_2 - t_1)}$.$\alpha = \frac{6 - 4}{4(100 - 0)} = \frac{2}{400} = 0.005^{\circ} C^{-1}$.

Class 12 Physics Current Electricity Meter Bridge

Difficult

In an experiment to determine the temperature coefficient of resistance of a conductor,a coil of wire $X$ is immersed in a liquid. It is heated by an external agent. $A$ meter bridge setup is used to determine the resistance of the coil $X$ at different temperatures. The balancing points measured at temperatures $t_1=0^{\circ} C$ and $t_2=100^{\circ} C$ are $50 \ cm$ and $60 \ cm$ respectively. If the standard resistance taken out is $S=4 \ \Omega$ in both trials,the temperature coefficient of the coil is

KCET 2024 All KCET

A
$0.05^{\circ} C^{-1}$
B
$0.02^{\circ} C^{-1}$
C
$0.005^{\circ} C^{-1}$
D
$2.0^{\circ} C^{-1}$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Current Electricity

Subtopic

Meter Bridge

Previous Year

KCET 2024 Paper All KCET years →

$A$ meter bridge is set up as shown to determine the end corrections at $A$ and $B$. When a resistance of $15\,\Omega$ is used in the left gap and $20\,\Omega$ in the right gap,the null point is obtained at a distance of $42\,cm$ from $A$. When these resistances are interchanged,the null point is obtained at a distance of $57\,cm$ from $A$. The values of the end corrections are:

Easy

View Solution

In a metre bridge experiment (see figure), the positions of the cell, $E$, and galvanometer, $G$, are interchanged. We shall observe in the galvanometer:

MediumNEET 2026

View Solution

$A$ wire of length $10 \ cm$ and radius $\sqrt{7} \times 10^{-4} \ m$ is connected across the right gap of a meter bridge. When a resistance of $4.5 \ \Omega$ is connected in the left gap using a resistance box,the balance length is found to be at $60 \ cm$ from the left end. If the resistivity of the wire is $R \times 10^{-7} \ \Omega \ m$,then the value of $R$ is:

DifficultJEE MAIN 2024

View Solution

In a metre-bridge,when a resistance in the left gap is $2 \ \Omega$ and an unknown resistance is in the right gap,the balance length is found to be $40 \ cm$. On shunting the unknown resistance with $2 \ \Omega$,the balance length changes by: (in $cm$)

DifficultJEE MAIN 2024

View Solution

In a meter bridge (Figure), the null point is found at a distance of $33.7 \; cm$ from $A$. If now a resistance of $12 \; \Omega$ is connected in parallel with $S$, the null point occurs at $51.9 \; cm$. Determine the values of $R$ and $S$.

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Similar Questions

In a metre bridge experiment (see figure), the positions of the cell, $E$, and galvanometer, $G$, are interchanged. We shall observe in the galvanometer:

In a metre-bridge,when a resistance in the left gap is $2 \ \Omega$ and an unknown resistance is in the right gap,the balance length is found to be $40 \ cm$. On shunting the unknown resistance with $2 \ \Omega$,the balance length changes by: (in $cm$)

In a meter bridge (Figure), the null point is found at a distance of $33.7 \; cm$ from $A$. If now a resistance of $12 \; \Omega$ is connected in parallel with $S$, the null point occurs at $51.9 \; cm$. Determine the values of $R$ and $S$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module