(A) For a parallel-plate capacitor,the charges on the facing surfaces are equal in magnitude and opposite in sign. Therefore,$Q_2 = -Q_3$.The potentia

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(A) For a parallel-plate capacitor,the charges on the facing surfaces are equal in magnitude and opposite in sign. Therefore,$Q_2 = -Q_3$.The potential difference $V$ between the plates is given by the charge on the inner surface divided by the capacitance $C$ of the capacitor.$V = \frac{Q_2}{C}$Since $Q_3 = -Q_2$,we can write $Q_2 = \frac{Q_2 - Q_3}{2}$.Substituting this into the potential difference formula:$V = \frac{Q_2 - Q_3}{2C}$

Class 12 Physics Electric Potential and Capacitance Parallel Plate Capacitor

Medium

In an insulated parallel-plate capacitor of capacitance $C$,the four surfaces have charges $Q_1, Q_2, Q_3$ and $Q_4$ as shown. The potential difference between the plates is

A
$\frac{Q_2 - Q_3}{2C}$
B
$\frac{Q_2 + 2Q_3}{2C}$
C
$\frac{Q_1 + Q_4}{2C}$
D
$\frac{Q_1 + Q_2 + Q_3 + Q_4}{2C}$

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Class 12

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Electric Potential and Capacitance

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Parallel Plate Capacitor

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In an insulated parallel-plate capacitor of capacitance $C$,the four surfaces have charges $Q_1, Q_2, Q_3$ and $Q_4$ as shown. The potential difference between the plates is

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$A$ parallel plate air capacitor is charged to a potential difference of $V \text{ volts}$. After disconnecting the charging battery,the distance between the plates of the capacitor is increased using an insulating handle. As a result,the potential difference between the plates

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