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(C) The acceptance angle $	heta_a$ is the maximum angle of incidence at the entrance of the optical fibre such that the light undergoes total interna

Vedclass · Accepted Answer

$0^{\circ}-30^{\circ}$

Vedclass · Answer

(C) The acceptance angle $	heta_a$ is the maximum angle of incidence at the entrance of the optical fibre such that the light undergoes total internal reflection at the core-cladding interface.For an optical fibre with core refractive index $\mu_1 = 1.5$ and cladding refractive index $\mu_2 = 1.414$, the acceptance angle $	heta_a$ is given by the formula:$\sin 	heta_a = \sqrt{\mu_1^2 - \mu_2^2}$Substituting the given values:$\sin 	heta_a = \sqrt{(1.5)^2 - (1.414)^2}$$\sin 	heta_a = \sqrt{2.25 - 1.999396} \approx \sqrt{0.2506} \approx 0.5006$$	heta_a = \sin^{-1}(0.5006) \approx 30^{\circ}$Thus, the range of the incident angle with the axis of the optical fibre for total internal reflection is $0^{\circ}$ to $30^{\circ}$.Therefore, option $C$ is correct.

In an optical fibre, the core and cladding are made with materials of refractive indices $1.5$ and $1.414$ respectively. To observe total internal reflection, what will be the range of the incident angle with the axis of the optical fibre?

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