In an optical instrument- microscope, the wav | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The resolving power $(RP)$ of a microscope is inversely proportional to the wavelength $(\lambda)$ of the light used, given by the formula: $RP \p

Vedclass · Accepted Answer

$3 : 4$

Vedclass · Answer

(D) The resolving power $(RP)$ of a microscope is inversely proportional to the wavelength $(\lambda)$ of the light used, given by the formula: $RP \propto \frac{1}{\lambda}$.Therefore, the ratio of the resolving power for $\lambda_1$ to that for $\lambda_2$ is given by:$\frac{RP_1}{RP_2} = \frac{\lambda_2}{\lambda_1}$.Given $\lambda_1 = 6800 	ext{ Å}$ and $\lambda_2 = 5100 	ext{ Å}$.Substituting the values:$\frac{RP_1}{RP_2} = \frac{5100}{6800} = \frac{51}{68} = \frac{3}{4}$.Thus, the ratio is $3 : 4$.

In an optical instrument- microscope, the wavelengths of light used are $\lambda_1 = 6800 \text{ Å}$ and $\lambda_2 = 5100 \text{ Å}$. The ratio of the resolving power of the microscope corresponding to $\lambda_1$ to that for $\lambda_2$ is

Similar Questions

Two-point white dots are $2 \,mm$ apart on a black paper. They are viewed by an eye of pupil diameter $3 \,mm$. What is the maximum distance at which these dots can be resolved by the eye (in $\,m$)? $(\lambda = 500 \,nm)$

Resolving power of a telescope can be increased by increasing

Assertion $(A):$ To increase the resolving power of a telescope,the aperture $(a)$ of the objective lens should be large.
Reason $(R):$ The resolving power of a telescope is given by $\frac{a}{1.22 \lambda}$.

The numerical aperture of a microscope is $0.12$, and the wavelength of light used is $600 \, nm$. Then its limit of resolution will be nearly $............. \, \mu m$.

When the object is self-luminous,the resolving power of a microscope is given by the expression

Vedclass Test Series

Exam Paper Generator

Online Exam Module