In an orbit,if the time of revolution of a satellite is $T$,then the potential energy $(PE)$ is proportional to:

$A$ satellite orbits the Earth at a height of $400 \; km$ above the surface. How much energy must be expended to rocket the satellite out of the Earth's gravitational influence? (Mass of the satellite $= 200 \; kg$; mass of the Earth $= 6.0 \times 10^{24} \; kg$; radius of the Earth $= 6.4 \times 10^{6} \; m$; $G = 6.67 \times 10^{-11} \; N m^{2} kg^{-2}$)

Choose the correct alternative:
$(a)$ If the zero of potential energy is at infinity,the total energy of an orbiting satellite is negative of its kinetic/potential energy.
$(b)$ The energy required to launch an orbiting satellite out of Earth's gravitational influence is more/less than the energy required to project a stationary object at the same height (as the satellite) out of Earth's influence.

Obtain an expression for the total energy of a satellite revolving around the Earth.

What is the binding energy of a satellite? Write its equation.

If the time period of revolution of a satellite is $T$,then its kinetic energy is proportional to