In an ordinary year,March begins on the same | vedclass

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(A) In an ordinary year,the number of days in each month is as follows: $January (31)$,$February (28)$,$March (31)$,$April (30)$,$May (31)$,$June (30)

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$February$ and $November$

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(A) In an ordinary year,the number of days in each month is as follows: $January (31)$,$February (28)$,$March (31)$,$April (30)$,$May (31)$,$June (30)$,$July (31)$,$August (31)$,$September (30)$,$October (31)$,$November (30)$,$December (31)$.To find the same starting day,the number of odd days between the start of two months must be a multiple of $7$.For $February$: The number of days in $January$ is $31$. $31 \pmod 7 = 3$. This does not match.Wait,in an ordinary year,$February$ starts on the same day as $March$ because $February$ has $28$ days $(28 \pmod 7 = 0)$.For $November$: The number of odd days from $March$ to $November$ is: $March (3) + April (2) + May (3) + June (2) + July (3) + August (3) + September (2) + October (3) = 21$. Since $21 \pmod 7 = 0$,$March$ and $November$ start on the same day.Thus,$March$ begins on the same day as $February$ and $November$.

In an ordinary year,$March$ begins on the same day of the week as which other month?

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