In aqueous solution, fluorine is a stronger o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The oxidizing power of a halogen in aqueous solution depends on the overall energy change involved in the process: $\frac{1}{2}X_2(g) + e^- \right

Vedclass · Accepted Answer

Ionization potential

Vedclass · Answer

(C) The oxidizing power of a halogen in aqueous solution depends on the overall energy change involved in the process: $\frac{1}{2}X_2(g) + e^- \rightarrow X^-(aq)$. This process involves three steps: $(1)$ Enthalpy of dissociation $(\frac{1}{2} \Delta H_{diss})$, $(2)$ Electron affinity $(\Delta H_{eg})$, and $(3)$ Enthalpy of hydration $(\Delta H_{hyd})$. Ionization potential is related to the removal of an electron, which is not involved in the reduction process of halogens to halide ions. Therefore, it is not a factor determining the oxidizing strength in aqueous solution.

In aqueous solution, fluorine is a stronger oxidizing agent than chlorine. This is due to all of the following factors $EXCEPT$:

Similar Questions

Which of the following groups of elements form anions?

Which one of the following is a pseudohalide?

Which of the following orders is not true for $HClO < HClO_2 < HClO_3 < HClO_4$?

Which of the following statements is correct?

Select the wrong chemical reaction among the following:

Vedclass Test Series

Exam Paper Generator

Online Exam Module