In the Bohr series of lines of the hydrogen s | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The red end of the hydrogen spectrum corresponds to the visible region,which is the Balmer series.For the Balmer series,the lower energy level is

Vedclass · Accepted Answer

$5 \rightarrow 2$

Vedclass · Answer

(D) The red end of the hydrogen spectrum corresponds to the visible region,which is the Balmer series.For the Balmer series,the lower energy level is $n_1 = 2$.The lines in the Balmer series are transitions from $n_2 = 3, 4, 5, 6, \dots$ to $n_1 = 2$.The first line (closest to the red end) is $3 \rightarrow 2$.The second line is $4 \rightarrow 2$.The third line from the red end is $5 \rightarrow 2$.Therefore,the transition is $5 \rightarrow 2$.

In the Bohr series of lines of the hydrogen spectrum,the third line from the red end corresponds to which one of the following inter-orbit transitions in an atom of hydrogen?

Similar Questions

The equation of the locus of $z$ such that $\left|\frac{z-i}{z+i}\right|=2$,where $z=x+iy$ is a complex number,is

Two waves $Y_1 = 0.25 \sin 316 t$ and $Y_2 = 0.25 \sin 310 t$ are propagating in the same direction. The number of beats produced per second is

If the mean of a Poisson distribution is $\frac{1}{2}$,then the ratio of $P(X=3)$ to $P(X=2)$ is

Which hormone causes stunted growth in pea?

Which of the following lacks a capsid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module