In the bromination of propyne,1,1,2,2-tetrabr | vedclass

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(D) The chemical reaction is: $CH_3-C \equiv CH + 2Br_2 ightarrow CH_3-CBr_2-CHBr_2$$1$. Molar mass of $Br_2 = 2 	imes 80 = 160 \; g/mol$.$2$. Mola

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$3$

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(D) The chemical reaction is: $CH_3-C \equiv CH + 2Br_2 ightarrow CH_3-CBr_2-CHBr_2$$1$. Molar mass of $Br_2 = 2 	imes 80 = 160 \; g/mol$.$2$. Molar mass of $1,1,2,2-$tetrabromopropane $(C_3H_4Br_4)$ $= (3 	imes 12) + (4 	imes 1) + (4 	imes 80) = 36 + 4 + 320 = 360 \; g/mol$.$3$. According to the stoichiometry,$2 \; mol$ of $Br_2$ produces $1 \; mol$ of $1,1,2,2-$tetrabromopropane.$4$. Moles of $Br_2$ used $= \frac{1 \; g}{160 \; g/mol} = 0.00625 \; mol$.$5$. Theoretical moles of $1,1,2,2-$tetrabromopropane $= \frac{0.00625}{2} = 0.003125 \; mol$.$6$. Theoretical mass of $1,1,2,2-$tetrabromopropane $= 0.003125 \; mol 	imes 360 \; g/mol = 1.125 \; g$.$7$. Actual yield $(27\%)$ $= 1.125 \; g 	imes 0.27 = 0.30375 \; g$.$8$. Expressing in $	imes 10^{-1} \; g$: $0.30375 = 3.0375 	imes 10^{-1} \; g$.$9$. Nearest integer is $3$.

In the bromination of propyne,$1,1,2,2-$tetrabromopropane is obtained in $27\%$ yield. The amount of $1,1,2,2-$tetrabromopropane obtained from $1 \; g$ of bromine $(Br_2)$ in this reaction is $\dots \; \times 10^{-1} \; g$. (Nearest integer)
(Molar mass: Bromine $(Br)$ $= 80 \; g/mol$)

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In the bromination of propyne,$1,1,2,2-$tetrabromopropane is obtained in $27\%$ yield. The amount of $1,1,2,2-$tetrabromopropane obtained from $1 \; g$ of bromine $(Br_2)$ in this reaction is $\dots \; \times 10^{-1} \; g$. (Nearest integer)(Molar mass: Bromine $(Br)$ $= 80 \; g/mol$)