In Calvin cycle,if one molecule of RuBP is ca | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In the Calvin cycle,the primary carboxylation step involves the enzyme $RuBisCO$,which catalyzes the reaction between one molecule of $RuBP$ ($5$-

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(A) In the Calvin cycle,the primary carboxylation step involves the enzyme $RuBisCO$,which catalyzes the reaction between one molecule of $RuBP$ ($5$-carbon sugar) and one molecule of $CO_2$.This reaction forms an unstable $6$-carbon intermediate,which immediately undergoes hydrolysis to produce $2$ molecules of $3$-phosphoglyceric acid ($PGA$,a $3$-carbon compound).Therefore,the carboxylation of one molecule of $RuBP$ results in the formation of $2$ molecules of $PGA$.

In Calvin cycle,if one molecule of $RuBP$ is carboxylated then how many $PGA$ molecules will be formed?

Similar Questions

The total requirement of $ATP$ and $NADPH$ for each molecule of $CO_2$ fixed and reduced in photosynthesis in the Calvin cycle is

In the $C_3$ pathway,the first stable product is $P$,and in the $C_4$ pathway,the first stable product is $Q$. Choose the correct option for $P$ and $Q$.

The enzyme required for carboxylation in the Calvin cycle is:

Suspension of isolated thylakoids in a culture medium containing $CO_2$ and $H_2O$ does not produce hexose due to the absence of which of the following?

How many turns of Calvin cycle are required for the formation of three molecules of glucose?

Vedclass Test Series

Exam Paper Generator

Online Exam Module