In case of heteronuclear diatomics of the typ | vedclass

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(B) In a heteronuclear diatomic molecule $AB$, if $A$ is more electronegative than $B$, the bonding molecular orbital is closer in energy to the atomi

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(B) In a heteronuclear diatomic molecule $AB$, if $A$ is more electronegative than $B$, the bonding molecular orbital is closer in energy to the atomic orbital of the more electronegative atom $A$.Consequently, the electron density in the bonding molecular orbital is concentrated more towards the more electronegative atom $A$.Thus, the bonding molecular orbital resembles the character of $A$ more than that of $B$.

In case of heteronuclear diatomics of the type $AB$, where $A$ is more electronegative than $B$, the bonding molecular orbital resembles the character of $A$ more than that of $B$. The statement

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