In common emitter mode of a transistor, the d.c. current gain $(\beta)$ is $20$ and the emitter current $(I_E)$ is $7 \text{ mA}$. The collector current $(I_C)$ is: (in $/3 \text{ mA}$)

In a common emitter amplifier,the input resistance is $1000 \Omega$,the peak value of the input signal voltage is $5 mV$,and $\beta = 60$. The peak value of the output current is:

In a transistor circuit, when the base current is increased by $50 \mu A$ keeping the collector voltage fixed at $2 \ V$, the collector current increases by $1 \ mA$. The current gain of the transistor is

For the given bipolar junction transistor,find the approximate value of $I_B$,if $V_{CC} = 9 \ V$,$V_{BB} = 1.5 \ V$,$R_C = 13 \ k\Omega$,$R_E = 17 \ k\Omega$,and $\beta = 100$. (Assume the transistor is in active mode and $V_{BE} = 0.7 \ V$)

$A$ $CE$ amplifier has a voltage gain of $G$. The transistor used has a transconductance of $0.03 \ mho$ and a current gain of $25$. If this transistor is replaced by another transistor with a transconductance of $0.02 \ mho$ and a current gain of $20$,the new voltage gain will be ........

For a $CE$ transistor amplifier,the audio signal voltage across the collector resistance of $2.0\,k\Omega$ is $2.0\,V$. Suppose the current amplification factor of the transistor is $100$. What should be the value of $R_B$ (in $k\Omega$) in series with $V_{BB}$ supply of $2.0\,V$ if the $dc$ base current has to be $10$ times the signal current?