(A) The lanthanoids exhibit a common oxidation state of $+3$. Not all members exhibit a $+4$ oxidation state; only a few,such as $Ce^{+4}$,$Pr^{+4}$,$

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Availability of $4f$ electrons results in the formation of compounds in $+4$ state for all the members of the series.

(A) The lanthanoids exhibit a common oxidation state of $+3$. Not all members exhibit a $+4$ oxidation state; only a few,such as $Ce^{+4}$,$Pr^{+4}$,$Nd^{+4}$,$Tb^{+4}$,and $Dy^{+4}$,show this state due to stable configurations. Therefore,the statement that all members form compounds in the $+4$ state is incorrect.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

In the context of the lanthanoids,which of the following statements is not correct?

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A
Availability of $4f$ electrons results in the formation of compounds in $+4$ state for all the members of the series.
B
There is a gradual decrease in the radii of the members with increasing atomic number in the series.
C
All the members exhibit $+3$ oxidation state.
D
Because of similar properties,the separation of lanthanoids is not easy.