In the context of the lanthanoids,which of th | vedclass

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(D) Lanthanoids exhibit a common $+3$ oxidation state.The $4f$ electrons are deeply buried and shielded by $5s$,$5p$,and $5d$ orbitals,making them les

Vedclass · Accepted Answer

Availability of $4f$ electrons results in the formation of compounds in $+4$ state for all the members of the series.

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(D) Lanthanoids exhibit a common $+3$ oxidation state.The $4f$ electrons are deeply buried and shielded by $5s$,$5p$,and $5d$ orbitals,making them less available for bonding compared to $d$-block elements.While some lanthanoids like $Ce$ $(+4)$ and $Tb$ $(+4)$ show $+4$ oxidation states due to stable electronic configurations (like $f^0$ or $f^7$),it is not a property of all members of the series.Therefore,the statement that all members form compounds in the $+4$ state is incorrect.

In the context of the lanthanoids,which of the following statements is not correct?

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Choose the most appropriate answer from the options given below:

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