In deriving the kinetic gas equation,use is m | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The kinetic gas equation is derived as $PV = \frac{1}{3} m N u_{rms}^2$. In this derivation,the pressure is related to the mean square velocity of

Vedclass · Accepted Answer

The square root of the average square velocity of the molecules

Vedclass · Answer

(C) The kinetic gas equation is derived as $PV = \frac{1}{3} m N u_{rms}^2$. In this derivation,the pressure is related to the mean square velocity of the gas molecules. By definition,the root mean square velocity $(u_{rms})$ is the square root of the mean of the squares of the velocities of individual molecules,i.e.,$u_{rms} = \sqrt{\frac{u_1^2 + u_2^2 + ... + u_n^2}{n}}$. Therefore,it is the square root of the average square velocity of the molecules.

In deriving the kinetic gas equation,use is made of the root mean square velocity of the molecules because it is

Similar Questions

Which of the following equations does not represent the root mean square velocity $(u_{rms})$?

The following graph is obtained for a gas at different temperatures $T_1$,$T_2$,$T_3$. What is the correct order of temperature? ($x$-axis $=$ velocity; $y$-axis $=$ number of molecules)

What is the $rms$ velocity of $O_2$ at $STP$ (in $cm/s$)?

At the same temperature,the root mean square velocities of two gases are $v_1$ and $v_2$,and their molar masses are $m_1$ and $m_2$ respectively. Which of the following relations is correct?

Which of the following gases has the highest value of $RMS$ velocity at $298 \ K$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module