In the dimer of phosphorus pentaoxide (P_4O_{ | vedclass

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Question

(A) The structure of $P_4O_{10}$ consists of a tetrahedral arrangement of four phosphorus atoms.Each phosphorus atom is bonded to three oxygen atoms v

Vedclass · Accepted Answer

$P-O-P > P=O > P-P$

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(A) The structure of $P_4O_{10}$ consists of a tetrahedral arrangement of four phosphorus atoms.Each phosphorus atom is bonded to three oxygen atoms via $P-O-P$ bridges,and one terminal oxygen atom via a $P=O$ double bond.Counting the bonds in the structure:$1$. Total $P-O-P$ bonds = $6$.$2$. Total $P=O$ bonds = $4$.$3$. Total $P-P$ bonds = $0$.Therefore,the order is $P-O-P (6) > P=O (4) > P-P (0)$.

In the dimer of phosphorus pentaoxide $(P_4O_{10})$,what is the correct order of the number of $P-O-P$,$P=O$,and $P-P$ bonds?

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