In Duma's method of estimation of nitrogen,0. | vedclass

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(B) In Duma's method,the pressure of dry nitrogen is calculated by subtracting the aqueous tension from the total pressure: $P_{N_2} = 758 \, mm - 14

Vedclass · Accepted Answer

$19$

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(B) In Duma's method,the pressure of dry nitrogen is calculated by subtracting the aqueous tension from the total pressure: $P_{N_2} = 758 \, mm - 14 \, mm = 744 \, mm \, Hg$.Using the ideal gas equation at $STP$ $(P_1V_1/T_1 = P_2V_2/T_2)$:$V_{STP} = \frac{P_{N_2} 	imes V_{obs} 	imes 273}{760 	imes T} = \frac{744 	imes 30 	imes 273}{760 	imes 287} \approx 27.935 \, mL$.Since $22400 \, mL$ of $N_2$ at $STP$ weighs $28 \, g$,the mass of $N_2$ obtained is:$Mass_{N_2} = \frac{28 	imes 27.935}{22400} \approx 0.03492 \, g$.Percentage of nitrogen = $\frac{Mass_{N_2}}{Mass_{compound}} 	imes 100 = \frac{0.03492}{0.1840} 	imes 100 \approx 18.98 \%$.Rounding off to the nearest integer,we get $19 \% $.

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