In each of the following questions a number s | vedclass

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(C) The given series follows the pattern: $T_{n+1} = T_n 	imes (6-n) - (7-n) 	imes (6-n)$ for $n=0, 1, 2, 3, 4$.Specifically:$30 = 12 	imes 6 - 7 \

Vedclass · Accepted Answer

$2808$

Vedclass · Answer

(C) The given series follows the pattern: $T_{n+1} = T_n 	imes (6-n) - (7-n) 	imes (6-n)$ for $n=0, 1, 2, 3, 4$.Specifically:$30 = 12 	imes 6 - 7 	imes 6 = 72 - 42 = 30$$120 = 30 	imes 5 - 6 	imes 5 = 150 - 30 = 120$$460 = 120 	imes 4 - 5 	imes 4 = 480 - 20 = 460$$1368 = 460 	imes 3 - 4 	imes 3 = 1380 - 12 = 1368$$2730 = 1368 	imes 2 - 3 	imes 2 = 2736 - 6 = 2730$Applying the same pattern to the second series starting with $16$:$(a) = 16 	imes 6 - 7 	imes 6 = 96 - 42 = 54$$(b) = 54 	imes 5 - 6 	imes 5 = 270 - 30 = 240$$(c) = 240 	imes 4 - 5 	imes 4 = 960 - 20 = 940$$(d) = 940 	imes 3 - 4 	imes 3 = 2820 - 12 = 2808$Therefore,the value in place of $(d)$ is $2808$.

$12$	$30$	$120$	$460$	$1368$	$2730$
$16$	$(a)$	$(b)$	$(c)$	$(d)$	$(e)$

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