In the figure,two blocks M and m are tied tog | vedclass

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(C) For the system to accelerate,the driving force must overcome the limiting friction force acting on block $M$.$1$. The limiting friction force on b

Vedclass · Accepted Answer

The system will accelerate only when $m > \mu M$.

Vedclass · Answer

(C) For the system to accelerate,the driving force must overcome the limiting friction force acting on block $M$.$1$. The limiting friction force on block $M$ is $f_{max} = \mu N = \mu M g$,where $N = M g$ is the normal force.$2$. The driving force acting on the system is the weight of the hanging block $m$,which is $m g$.$3$. The system will start to accelerate only when the driving force exceeds the limiting friction force:$m g > \mu M g$$4$. Dividing both sides by $g$,we get:$m > \mu M$Therefore,the system will accelerate only when $m > \mu M$.

In the figure,two blocks $M$ and $m$ are tied together with an inextensible and light string. The mass $M$ is placed on a rough horizontal surface with a coefficient of friction $\mu$,and the mass $m$ is hanging vertically. The pulley is frictionless. Choose the correct statement$(s)$.

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