In general,in an alternating current circuit:

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Question

(A) For an alternating current given by $I = I_0 \sin(\omega t)$,the average value of current over a complete cycle is given by $I_{avg} = \frac{1}{T}

Vedclass · Accepted Answer

The average value of current is zero

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(A) For an alternating current given by $I = I_0 \sin(\omega t)$,the average value of current over a complete cycle is given by $I_{avg} = \frac{1}{T} \int_0^T I_0 \sin(\omega t) dt = 0$. This is because the positive and negative half-cycles cancel each other out.The average value of the square of the current is $I_{rms}^2 = \frac{I_0^2}{2}$,which is not zero.Average power dissipation is given by $P_{avg} = V_{rms} I_{rms} \cos(\phi)$,which is generally not zero unless the circuit is purely reactive.The phase difference between voltage and current is not necessarily zero; it depends on the components $(R, L, C)$ in the circuit.

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