In the given circuit,find the value of V. (in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To find the equivalent resistance of the circuit,we first simplify the network. Let the nodes be labeled as shown in the solution image. The resis

Vedclass · Accepted Answer

$80$

Vedclass · Answer

(B) To find the equivalent resistance of the circuit,we first simplify the network. Let the nodes be labeled as shown in the solution image. The resistors $20 \ \Omega$,$100 \ \Omega$,and $25 \ \Omega$ are connected in parallel between nodes $a$ and $b$. The equivalent resistance $R_p$ of these three resistors is given by: $\frac{1}{R_p} = \frac{1}{20} + \frac{1}{100} + \frac{1}{25} = \frac{5 + 1 + 4}{100} = \frac{10}{100} = \frac{1}{10} \ \Omega^{-1}$. Therefore,$R_p = 10 \ \Omega$. Now,the circuit consists of a $4 \ \Omega$ resistor in series with the parallel combination $R_p = 10 \ \Omega$,and a $6 \ \Omega$ resistor,all in series. The total equivalent resistance $R_{eq}$ is: $R_{eq} = 4 \ \Omega + 10 \ \Omega + 6 \ \Omega = 20 \ \Omega$. Given the total current $I = 4 \ A$,the voltage $V$ is: $V = I 	imes R_{eq} = 4 \ A 	imes 20 \ \Omega = 80 \ V$.

In the given circuit,find the value of $V$. (in $V$)

Similar Questions

Two bulbs,one of $50\, W$ and another of $25\, W$,are connected in series to the mains. The ratio of the currents through them is:

Find the equivalent resistance between point $A$ and $B$ in the following circuit. (The resistance of each resistor is $R$)

Two resistors are connected $(a)$ in series $(b)$ in parallel. The equivalent resistance in the two cases are $9 \ \Omega$ and $2 \ \Omega$ respectively. Then the resistances of the component resistors are

$A$ wire has a resistance of $24 \ \Omega$ and is bent into the shape shown below. The effective resistance between $A$ and $B$ is ............. $\Omega$.

$n$ equal resistors are first connected in series and then connected in parallel. What is the ratio of the maximum to the minimum resistance?

Vedclass Test Series

Exam Paper Generator

Online Exam Module