In how many ways can five examination papers | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Total number of arrangements of $5$ distinct examination papers is $5! = 5 	imes 4 	imes 3 	imes 2 	imes 1 = 120$.To find the number of ways w

Vedclass · Accepted Answer

$72$

Vedclass · Answer

(D) Total number of arrangements of $5$ distinct examination papers is $5! = 5 	imes 4 	imes 3 	imes 2 	imes 1 = 120$.To find the number of ways where physics and chemistry papers never come together,we first calculate the number of ways they $DO$ come together.Treat the physics and chemistry papers as a single unit. Now,we have $4$ units to arrange (the single unit of physics-chemistry + the remaining $3$ papers),which can be done in $4!$ ways.Within the single unit,the physics and chemistry papers can be arranged in $2!$ ways.Therefore,the number of arrangements where they come together is $4! 	imes 2! = 24 	imes 2 = 48$.The number of ways they never come together is the total arrangements minus the arrangements where they are together: $120 - 48 = 72$.

In how many ways can five examination papers be arranged so that physics and chemistry papers never come together?

Similar Questions

The principal wants to arrange $5$ students on the platform such that the boy $SUNIL$ occupies the second position and such that the girl $GITA$ is always adjacent to the girl $NITA$. How many such arrangements are possible?

When ten persons shake hands with one another,in how many ways is it possible?

If $110$ triangles can be formed by joining $10$ points as vertices,in which $n$ points are collinear,then the value of $n$ is:

How many $3$-letter words can be formed from the letters of the word '$EXPERTISE$',if repetition of letters is not allowed?

The value of $r$ for which $^{15}C_{r + 3} = {}^{15}C_{2r - 6}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module