In the hydrogen spectrum,the shortest wavelength in the Balmer series is $\lambda$. The shortest wavelength in the Brackett series is $........\,\lambda$.

When an electron in a hydrogen atom jumps to the innermost orbit,the radiation emitted belongs to which one of the following series?

In a hydrogen sample,if the atoms are excited to states with principal quantum number $n = 20$,then the number of different wavelengths which may be observed in the spectrum is:

Find the ratio of the wavelength of the first line of the Lyman series for a doubly ionized lithium atom $(Li^{2+})$ to the wavelength of the first line of the Lyman series for deuterium $(D)$.

For the wavelength of visible radiation of the hydrogen spectrum,Balmer gave an equation as $\lambda = \frac{(k m^2)}{(m^2 - 4)}$,where $m$ is an integer. The value of $k$ in terms of Rydberg's constant $R$ is

The difference between the frequencies of the first and second Lyman lines of the hydrogen atom is (where $R$ is the Rydberg constant and $c$ is the speed of light in vacuum).