In non-uniform circular motion,the ratio of tangential to radial acceleration is ($r=$ radius,$\alpha=$ angular acceleration,$V=$ linear velocity).

$A$ particle is moving on a circular path with constant speed,then its acceleration will be

What is the angle between the tangential component and the radial component of linear acceleration for circular motion (in $^{\circ}$)?

The angular speed of a particle moving in a circular path is doubled. Then, the centripetal acceleration of the particle is

$A$ body of mass $2 \,kg$ moves in a horizontal circular path of radius $5 \,m$. At an instant, its speed is $2 \sqrt{5} \,m/s$ and is increasing at the rate of $3 \,m/s^2$. The magnitude of the net force acting on the body at that instant is: (in $\,N$)

What happens to the centripetal acceleration of a revolving body if you double the orbital speed $v$ and halve the angular velocity $\omega$?