In the nuclear reaction _2He^4 + _zX^A to _{z | vedclass

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(D) The given nuclear reaction is $_2He^4 + _zX^A 	o _{z+2}Y^{A+3} + A$.Applying the law of conservation of mass number:$4 + A = A + 3 + m$,where $m$

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(D) The given nuclear reaction is $_2He^4 + _zX^A 	o _{z+2}Y^{A+3} + A$.Applying the law of conservation of mass number:$4 + A = A + 3 + m$,where $m$ is the mass number of $A$.$4 + A = A + 3 + m \Rightarrow m = 1$.Applying the law of conservation of atomic number (charge):$2 + z = z + 2 + q$,where $q$ is the atomic number of $A$.$2 + z = z + 2 + q \Rightarrow q = 0$.$A$ particle with mass number $1$ and atomic number $0$ is a neutron $(_{0}n^1)$.Therefore,$A$ denotes a neutron.

In the nuclear reaction $_2He^4 + _zX^A \to _{z+2}Y^{A+3} + A$,$A$ denotes:

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