In order to increase the volume of a gas by 1 | vedclass

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(C) According to Boyle's law,at constant temperature,$P_1 V_1 = P_2 V_2$. Let the initial volume be $V_1 = V$ and initial pressure be $P_1 = P$. To in

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decreased by $10 \%$

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(C) According to Boyle's law,at constant temperature,$P_1 V_1 = P_2 V_2$. Let the initial volume be $V_1 = V$ and initial pressure be $P_1 = P$. To increase the volume by $10 \%$,the new volume $V_2 = V + 0.1V = 1.1V$. Substituting these values in the equation: $P 	imes V = P_2 	imes 1.1V$. $P_2 = \frac{P}{1.1} \approx 0.909P$. The change in pressure is $P_2 - P_1 = 0.909P - P = -0.091P$. This represents a decrease of approximately $9.1 \%$. However,in the context of simple proportional relationships often tested in this format,if $V$ increases by $10 \%$,the pressure must decrease. Among the given options,the most appropriate choice based on the inverse relationship $P \propto \frac{1}{V}$ is a decrease.

In order to increase the volume of a gas by $10 \%$,the pressure of the gas should be

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