In reaction $(1)$, $XeF_6$ undergoes complete hydrolysis to form $HF$ and $X$. In reaction $(2)$, $XeF_6$ undergoes partial hydrolysis to form $HF$, $Y$, and $Z$. The products $X, Y, Z$ respectively, are
- A$XeO_3, XeOF_4, XeO_2 F_2$
- B$XeO_3, XeO_2 F_2, XeOF_4$
- C$Xe, XeOF_4, XeO_2 F_2$
- D$XeO_3, O_2, XeO_2 F_2$
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