In $S.H.M.$,maximum acceleration is at

The displacement of an oscillating particle varies with time $t$ (in seconds) according to the equation $y (cm) = \sin \left[ \frac{\pi}{2} \left( \frac{t}{2} + \frac{1}{3} \right) \right]$. The maximum acceleration of the particle is approximately ..... $cm/s^2$.

The maximum acceleration of a particle in $SHM$ is made two times keeping the maximum speed constant. This is possible when:

Give the direction of velocity and acceleration of an $SHM$ particle.

$A$ point mass oscillates along the $x$-axis according to the law $x=x_0 \cos(\omega t - \frac{\pi}{4})$. If the acceleration of the particle is written as $a=A \cos(\omega t + \delta)$,then:

The displacement versus time graph of $SHM$ is shown. Which of the following is its acceleration versus time graph?