In solid CuSO_4 cdot 5H_2O,copper is coordina | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The correct answer is $(B)$.In the crystal structure of $CuSO_4 \cdot 5H_2O$,the $Cu^{2+}$ ion is coordinated to four water molecules in a square

Vedclass · Accepted Answer

Four water molecules

Vedclass · Answer

(B) The correct answer is $(B)$.In the crystal structure of $CuSO_4 \cdot 5H_2O$,the $Cu^{2+}$ ion is coordinated to four water molecules in a square planar arrangement.The remaining two coordination sites of the distorted octahedron are occupied by oxygen atoms from two different $SO_4^{2-}$ ions.The fifth water molecule is held by hydrogen bonding between the coordinated water molecules and the sulphate ions.

List $-I$	List $-II$
$A$. $[PtCl_4]^{2-}$	$I$. $sp^3d$
$B$. $BrF_5$	$II$. $d^2sp^3$
$C$. $PCl_5$	$III$. $dsp^2$
$D$. $[Co(NH_3)_6]^{3+}$	$IV$. $sp^3d^2$

In solid $CuSO_4 \cdot 5H_2O$,copper is coordinated to:

Similar Questions

The geometry and magnetic behaviour of the complex $[Ni(CO)_4]$ are

Which of the following statements is not true?

$Mn^{2+}$ forms a complex with $Br^{-}$ ion. The magnetic moment of the complex is $5.92 \ B.M.$ What could not be the probable formula and geometry of the complex?

Match List $-I$ with List $-II$:

List $-I$ List $-II$

$A$. $[PtCl_4]^{2-}$ $I$. $sp^3d$

$B$. $BrF_5$ $II$. $d^2sp^3$

$C$. $PCl_5$ $III$. $dsp^2$

$D$. $[Co(NH_3)_6]^{3+}$ $IV$. $sp^3d^2$

$[Mn(CO)_4 NO]$ is diamagnetic because

Vedclass Test Series

Exam Paper Generator

Online Exam Module