In terms of Charles' law,explain why $-273.15 \,^{\circ}C$ is the lowest possible temperature.

According to Charles' law,the volume of a gas is given by the equation: $V_{t} = V_{0} \left( \frac{273.15 + t}{273.15} \right)$ ... $(i)$
Substituting $t = -273.15 \,^{\circ}C$ into the equation:
$V_{-273.15} = V_{0} \left( \frac{273.15 - 273.15}{273.15} \right)$
$V_{-273.15} = V_{0} \left( \frac{0}{273.15} \right) = 0$
At $-273.15 \,^{\circ}C$,the volume of a hypothetical gas becomes zero. Since volume cannot be negative,this temperature represents the theoretical lower limit of temperature,known as absolute zero. In reality,all gases liquefy or solidify before reaching this temperature.