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(C) The conversion of $p$-nitrotoluene to $3$-bromo-$4$-chlorobenzoic acid involves the following steps:$1$. Electrophilic aromatic substitution: Brom

Vedclass · Accepted Answer

$(i) Br_2 / Fe, (ii) Fe / H^{+}, (iii) HONO, (iv) CuCl, (v) KMnO_4$

Vedclass · Answer

(C) The conversion of $p$-nitrotoluene to $3$-bromo-$4$-chlorobenzoic acid involves the following steps:$1$. Electrophilic aromatic substitution: Bromination of $p$-nitrotoluene using $Br_2 / Fe$ introduces a bromine atom at the ortho position relative to the methyl group.$2$. Reduction: The nitro group $(-NO_2)$ is reduced to an amino group $(-NH_2)$ using $Fe / H^+$.$3$. Diazotization: The amino group is converted to a diazonium salt $(-N_2^+Cl^-)$ using $HONO$ (nitrous acid) at $0-5 \ ^\circ C$.$4$. Sandmeyer reaction: The diazonium group is replaced by a chlorine atom using $CuCl$.$5$. Oxidation: The methyl group $(-CH_3)$ is oxidized to a carboxylic acid group $(-COOH)$ using $KMnO_4$.Thus,the correct sequence is $(i) Br_2 / Fe, (ii) Fe / H^{+}, (iii) HONO, (iv) CuCl, (v) KMnO_4$.

List-$I$	List-$II$
$A$. Amide	$I$. Carbylamine reaction
$B$. Nitrile	$II$. Hinsberg's reagent
$C$. $C_6H_5SO_2Cl$	$III$. Hofmann's bromamide reaction
$D$. $1^{\circ}$-Amine	$IV$. $LiAlH_4$

In the above conversion,the correct sequence of reagents to be added is:

Similar Questions

$A$ student has planned to prepare acetanilide from aniline using acetic anhydride. The student has started from $9.3 \ g$ of aniline. However, the student has managed to obtain $11 \ g$ of dry acetanilide. The $\%$ yield of this reaction is $.....$ (in $\%$)

The correct sequence of reagents for the following transformation is:

The end product $C$ of the following reaction is $C_2H_5NH_2$ $\xrightarrow{HNO_2} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{NH_3 (alc.)} C$

Predict the major product $G$ of the following reaction sequence starting from $p$-nitrotoluene.

Match the following:
List-$I$ List-$II$
$A$. Amide $I$. Carbylamine reaction
$B$. Nitrile $II$. Hinsberg's reagent
$C$. $C_6H_5SO_2Cl$ $III$. Hofmann's bromamide reaction
$D$. $1^{\circ}$-Amine $IV$. $LiAlH_4$

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