In the above reaction,the reagent A is : | vedclass

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Question

(C) The reaction shows the oxidation of an alkyl group (specifically a methyl group attached to a benzene ring) to a carboxylic acid group $(-COOH)$.A

Vedclass · Accepted Answer

Alkaline $KMnO_4, H^{+}$

Vedclass · Answer

(C) The reaction shows the oxidation of an alkyl group (specifically a methyl group attached to a benzene ring) to a carboxylic acid group $(-COOH)$.Alkaline $KMnO_4$ followed by acidic workup $(H^+)$ is a strong oxidizing agent that converts alkyl side chains on aromatic rings into carboxylic acid groups,regardless of the length of the alkyl chain,provided there is at least one benzylic hydrogen atom.Therefore,the reagent $A$ is alkaline $KMnO_4$ followed by $H^+$.

In the above reaction,the reagent $A$ is :

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