In the adjoining circuit diagram,the readings | vedclass

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(C) Let the resistance of the voltmeter be $R_v$. The voltmeter is connected in parallel with the resistor $R = 75 \ \Omega$.The total voltage across

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$300$

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(C) Let the resistance of the voltmeter be $R_v$. The voltmeter is connected in parallel with the resistor $R = 75 \ \Omega$.The total voltage across the parallel combination is $V = 120 \ V$.The current through the resistor $R$ is $I_R = \frac{V}{R} = \frac{120}{75} = 1.6 \ A$.The total current from the source is $I = 2 \ A$.The current through the voltmeter is $I_v = I - I_R = 2 - 1.6 = 0.4 \ A$.The resistance of the voltmeter is $R_v = \frac{V}{I_v} = \frac{120}{0.4} = 300 \ \Omega$.

In the adjoining circuit diagram,the readings of the ammeter and voltmeter are $2 \ A$ and $120 \ V$,respectively. If the value of $R$ is $75 \ \Omega$,then the voltmeter resistance will be (in $\Omega$):

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