In the Cannizzaro reaction given below,the slowest step is $:-$
$2Ph-CHO \xrightarrow{\stackrel{\ominus}{O}H} PhCH_2OH + PhCO_2^{\ominus}$

  • A
    The attack of $\stackrel{\ominus}{O}H$ at carbonyl group
  • B
    The transfer of hydride ion to carbonyl group
  • C
    The abstraction of proton from the carboxylic acid
  • D
    The deprotonation of $PhCH_2-OH$

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$Ph-CO-CHO \xrightarrow[\Delta]{conc. NaOH} \text{Product}$

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The value of $x$ in the above reaction is:

The major product formed in the following reaction is:

Identify the condensation product of the following reaction.
$R-CHO + NH_2OH \longrightarrow ?$

Which of the following reagents would carry out the following transformation?
$C_6H_5COCH_3 \rightarrow C_6H_5CH(OD)CH_3$ (Note: The product shows a deuterium atom attached to the chiral carbon,not the oxygen).

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