In the case of a $NAND$ gate,if $A$ and $B$ are the inputs and $Y$ is the output,then:
- A$Y=A \cdot B$
- B$Y=\overline{A-B}$
- C$Y=\overline{A+B}$
- D$Y=\overline{A \cdot B}$
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Similar Questions
Choose the correct logic circuit for the given truth table having inputs $A$ and $B$.
Inputs Inputs Outputs $A$ $B$ $Y$ $0$ $0$ $0$ $0$ $1$ $0$ $1$ $0$ $1$ $1$ $1$ $1$
| Inputs | Inputs | Outputs |
| $A$ | $B$ | $Y$ |
| $0$ | $0$ | $0$ |
| $0$ | $1$ | $0$ |
| $1$ | $0$ | $1$ |
| $1$ | $1$ | $1$ |
The logic gate equivalent to the given circuit diagram is:
If $X$ and $Y$ are the inputs, the given circuit works as . . . . . . .
DifficultJEE MAIN 2026
View SolutionAn $AND$ gate
Medium
View SolutionThe correct Boolean operation represented by the circuit diagram shown is:
MediumNEET 2019
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