In the circuit shown in the figure,$K$ is open. The charge on capacitor $C$ in the steady state is $q_1$. Now,the key $K$ is closed,and at the steady state,the charge on $C$ is $q_2$. The ratio of charges $\left( \frac{q_1}{q_2} \right)$ is:

When two identical capacitors are charged individually to different potentials and then connected in parallel,after disconnecting from the source . . . . . .

$A$ capacitor of capacitance $C = 900 \, pF$ is charged fully by a $100 \, V$ battery as shown in figure $(a)$. Then it is disconnected from the battery and connected to another uncharged capacitor of capacitance $C = 900 \, pF$ as shown in figure $(b)$. The electrostatic energy stored by the system in figure $(b)$ is $\dots \times 10^{-6} \, J$.

Three identical capacitors, each of capacitance $C$, are connected in series, resulting in a net capacitance $x$. If these three capacitors are then connected in parallel, what is the ratio of the energy stored in the series configuration to the energy stored in the parallel configuration, assuming both configurations are connected to the same voltage source $V$?

$A$ circuit is connected as shown in the figure with the switch $S$ open. When the switch is closed,the total amount of charge that flows from $Y$ to $X$ is

When we touch the terminals of a high voltage capacitor,even after the power supply has been disconnected,the capacitor has a tendency to: