In the circuit diagram shown in the adjoining | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The capacitors of $2\,\mu F$ and $3\,\mu F$ are connected in parallel. Their equivalent capacitance is $C_p = 2\,\mu F + 3\,\mu F = 5\,\mu F$.Now,

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The capacitors of $2\,\mu F$ and $3\,\mu F$ are connected in parallel. Their equivalent capacitance is $C_p = 2\,\mu F + 3\,\mu F = 5\,\mu F$.Now,the circuit consists of three capacitors of $12\,\mu F$,$5\,\mu F$,and $20\,\mu F$ connected in series between points $P$ and $Q$.The equivalent capacitance $C_{PQ}$ is given by the formula for series combination:$\frac{1}{C_{PQ}} = \frac{1}{12} + \frac{1}{5} + \frac{1}{20}$Taking the least common multiple $(LCM)$ of $12, 5,$ and $20$,which is $60$:$\frac{1}{C_{PQ}} = \frac{5 + 12 + 3}{60} = \frac{20}{60} = \frac{1}{3}$Therefore,$C_{PQ} = 3\,\mu F$.

In the circuit diagram shown in the adjoining figure,the resultant capacitance between $P$ and $Q$ is ........ $\mu F$.

Similar Questions

Three capacitors $2 \mu F$,$3 \mu F$,and $5 \mu F$ can withstand voltages up to $3 \, V$,$2 \, V$,and $1 \, V$ respectively. Their series combination can withstand a maximum voltage equal to.....$V$.

In the circuit shown in the figure,the effective capacitance between $A$ and $B$ is ...... $\mu F$.

The equivalent capacitance between points $A$ and $B$ as shown in the figure is:

We need to connect a capacitor of $16\ \mu F, 1000\ V$. However,we only have capacitors of $8\ \mu F, 250\ V$ available. How many such capacitors are required?

Five capacitors,each of value $1 \mu F$,are connected as shown in the figure. The equivalent capacitance between $A$ and $B$ is (in $\mu F$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module