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(D) The circuit consists of a branch with a capacitor $C$ connected in parallel to a series combination of three capacitors ($2C$,$C$,and $2C$).The po

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$30$

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(D) The circuit consists of a branch with a capacitor $C$ connected in parallel to a series combination of three capacitors ($2C$,$C$,and $2C$).The potential difference across the parallel branch is $60\,V$.For the series branch,the equivalent capacitance $C_{eq}$ is given by $\frac{1}{C_{eq}} = \frac{1}{2C} + \frac{1}{C} + \frac{1}{2C} = \frac{1+2+1}{2C} = \frac{4}{2C} = \frac{2}{C}$.Thus,$C_{eq} = \frac{C}{2}$.The total charge $Q$ flowing through this series branch is $Q = C_{eq} 	imes V = \frac{C}{2} 	imes 60 = 30C$.The potential difference across the capacitor $C$ (between points $M$ and $N$) is $V_{MN} = \frac{Q}{C} = \frac{30C}{C} = 30\,V$.

In the circuit shown,a potential difference of $60\,V$ is applied across $AB$. The potential difference between the points $M$ and $N$ is.....$V$

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