In the circuit shown, the reading of the amme | vedclass

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(B) When switch $S$ is open, the $2\, \Omega$ resistor in the upper branch is disconnected. The circuit consists of a $3\, \Omega$ resistor in series

Vedclass · Accepted Answer

$4\, A$ and $5\, A$

Vedclass · Answer

(B) When switch $S$ is open, the $2\, \Omega$ resistor in the upper branch is disconnected. The circuit consists of a $3\, \Omega$ resistor in series with a $2\, \Omega$ resistor.Total resistance $R_{eq} = 3\, \Omega + 2\, \Omega = 5\, \Omega$.The reading of the ammeter is $i = \frac{V}{R_{eq}} = \frac{20\, V}{5\, \Omega} = 4\, A$.When switch $S$ is closed, the two $2\, \Omega$ resistors are in parallel. The equivalent resistance of this parallel combination is $R_p = \frac{2\, \Omega 	imes 2\, \Omega}{2\, \Omega + 2\, \Omega} = 1\, \Omega$.The total resistance of the circuit is $R_{eq}' = 3\, \Omega + 1\, \Omega = 4\, \Omega$.The reading of the ammeter is $i' = \frac{V}{R_{eq}'} = \frac{20\, V}{4\, \Omega} = 5\, A$.Thus, the readings are $4\, A$ and $5\, A$ respectively.

In the circuit shown, the reading of the ammeter when switch $S$ is open and when switch $S$ is closed respectively are

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