In the circuit shown,the value of each resist | vedclass

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(D) The circuit can be simplified by identifying series and parallel combinations.$1$. The two resistors connected to point $C$ form a delta-star or c

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$8r / 7$

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(D) The circuit can be simplified by identifying series and parallel combinations.$1$. The two resistors connected to point $C$ form a delta-star or can be simplified by recognizing symmetry. Alternatively,observe the top triangle: the two resistors of resistance $r$ are in series,giving $2r$. This $2r$ is in parallel with the third resistor $r$ of the top triangle.$2$. The equivalent resistance of the top part is $R_{top} = (2r 	imes r) / (2r + r) = (2/3)r$.$3$. Now,this $R_{top}$ is in series with the two resistors connected to $A$ and $B$ respectively,but looking at the structure,we can simplify the network into a parallel combination of branches.$4$. The total resistance between $A$ and $B$ is found by reducing the network step-by-step to a single equivalent resistor,which results in $R_{eq} = 8r / 7$.

In the circuit shown,the value of each resistance is $r$. The equivalent resistance of the circuit between points $A$ and $B$ will be:

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