In the circuit shown, what will be the curren | vedclass

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(D) To determine if the Zener diode is in breakdown, we first calculate the voltage across the parallel combination of the $1 k\Omega$ resistor and th

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Zero

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(D) To determine if the Zener diode is in breakdown, we first calculate the voltage across the parallel combination of the $1 k\Omega$ resistor and the Zener diode without the Zener diode connected.Using the voltage divider rule, the voltage $V_{AB}$ across the $1 k\Omega$ resistor is:$V_{AB} = V_s 	imes \frac{R_{parallel}}{R_s + R_{parallel}} = 10 V 	imes \frac{1 k\Omega}{1 k\Omega + 1 k\Omega} = 10 V 	imes \frac{1}{2} = 5 V$.Since the voltage across the terminals $A$ and $B$ is $5 V$, which is less than the Zener breakdown voltage of $6 V$, the Zener diode does not conduct.Therefore, the current through the Zener diode is $0 A$ (Zero).

In the circuit shown, what will be the current through the $6 V$ zener diode?

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