In the circuit shown here,the voltages across $L$ and $C$ are respectively $300\, V$ and $400\, V$. The voltage $E$ of the $AC$ source is......$V$.

The current $I$,potential difference $V_L$ across the inductor,and potential difference $V_C$ across the capacitor in the circuit as shown in the figure are best represented vectorially as:

$A$ bulb and a capacitor are connected in series across an $AC$ supply. $A$ dielectric is then placed between the plates of the capacitor. The glow of the bulb:

In an $A.C.$ circuit,a resistance '$R$' is connected in series with an inductance '$L$'. If the phase angle between voltage and current is $45^{\circ}$,the value of inductive reactance will be $(\tan 45^{\circ} = 1)$.

In an $LC$ circuit,the inductance $L = 40 \; mH$ and capacitance $C = 100 \; \mu F$. If a voltage $V(t) = 10 \sin (314 t)$ is applied to the circuit,the current in the circuit is given by:

$A$ coil has self-inductance $L = 0.04 \ H$ and resistance $R = 12 \ \Omega$. When it is connected to a $220 \ V, 50 \ Hz$ supply,what will be the current flowing through the coil (in $A$)?