In the circuit shown in the figure, what is t | vedclass

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(A) Just after pressing the key $K$ (at $t = 0$), the inductor acts as an open circuit because it opposes any instantaneous change in current.Therefor

Vedclass · Accepted Answer

$\frac{5}{7} \, A$

Vedclass · Answer

(A) Just after pressing the key $K$ (at $t = 0$), the inductor acts as an open circuit because it opposes any instantaneous change in current.Therefore, the branch containing the inductor and the $8 \, \Omega$ resistor is effectively disconnected.The circuit simplifies to a $10 \, V$ battery in series with a $6 \, \Omega$ resistor and an $8 \, \Omega$ resistor connected in parallel to the source.However, since the inductor branch is open, the current $I_1$ flows through the $6 \, \Omega$ resistor and then entirely through the $8 \, \Omega$ resistor connected in parallel.The equivalent resistance of the circuit is $R_{eq} = 6 \, \Omega + 8 \, \Omega = 14 \, \Omega$.The current $I_1$ is given by $I_1 = \frac{V}{R_{eq}} = \frac{10 \, V}{14 \, \Omega} = \frac{5}{7} \, A$.

In the circuit shown in the figure, what is the value of $I_1$ just after pressing the key $K$?

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