In the circuit shown in the figure,K_1 is ope | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) When the key $K_1$ is open,no current flows through the resistor $R_2$. The capacitor $C$ is connected in parallel with the battery $E$ through th

Vedclass · Accepted Answer

$5/3$

Vedclass · Answer

(A) When the key $K_1$ is open,no current flows through the resistor $R_2$. The capacitor $C$ is connected in parallel with the battery $E$ through the resistor $R_1$. Since there is no current,there is no potential drop across $R_1$. Therefore,the voltage across the capacitor is $V_C = E$.The charge on the capacitor is $q_1 = CE$.When the key $K_1$ is closed,the circuit reaches a steady state where the capacitor acts as an open circuit. The resistors $R_1 = 2 \ \Omega$ and $R_2 = 3 \ \Omega$ are in series. The voltage across the capacitor $C$ is the voltage across the resistor $R_2$.Using the voltage divider rule,the voltage across $C$ is $V_C' = \frac{R_2}{R_1 + R_2} 	imes E = \frac{3}{2 + 3} 	imes E = \frac{3}{5} E$.The charge on the capacitor is $q_2 = C V_C' = C 	imes \frac{3}{5} E = \frac{3}{5} CE$.Calculating the ratio $q_1/q_2$:$\frac{q_1}{q_2} = \frac{CE}{\frac{3}{5} CE} = \frac{5}{3}$.

List-$I$	List-$II$
$(i)$ The equation of the polar of $(-5, 1)$ with respect to $C$	$(A)$ $y = 0$
$(ii)$ The equation of the tangent at $(8, 0)$ to $C$	$(B)$ $y = 6$
$(iii)$ The equation of the normal at $(2, 6)$ to $C$	$(C)$ $x + y = 7$
$(iv)$ The equation of the diameter of $C$ through $(8, 12)$	$(D)$ $13x + 5y = 98$
	$(E)$ $x = 8$

In the circuit shown in the figure,$K_1$ is open. The charge on capacitor $C$ in steady state is $q_1$. Now,the key is closed and at steady state,the charge on $C$ is $q_2$. The ratio of charges $q_1/q_2$ is

Similar Questions

If $k > 1$ and the determinant of the matrix $A^2$,where $A = \begin{bmatrix} k & k\alpha & \alpha \\ 0 & \alpha & k\alpha \\ 0 & 0 & k \end{bmatrix}$,is $k^2$,then $|\alpha|$ is equal to

Which of the following is the weakest base?

The equation of the sphere passing through the points $(1,0,0)$, $(0,1,0)$, and $(1,1,1)$ and having the smallest radius is:

$A$ uniform chain of length $L$ is lying on a horizontal table. If the coefficient of friction between the chain and the table top is $\mu$, what is the maximum length of the chain that can hang over the edge of the table without disturbing the rest of the chain on the table?

Vedclass Test Series

Exam Paper Generator

Online Exam Module