In the cobalt-carbonyl complex: [Co_{2}(CO)_{ | vedclass

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Question

(B) The structure of the cobalt-carbonyl complex $[Co_{2}(CO)_{8}]$ consists of two $Co$ atoms bonded to each other.$1$. Number of $Co-Co$ bonds $(X)$

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(B) The structure of the cobalt-carbonyl complex $[Co_{2}(CO)_{8}]$ consists of two $Co$ atoms bonded to each other.$1$. Number of $Co-Co$ bonds $(X)$: There is $1$ direct metal-metal bond between the two cobalt atoms. So,$X = 1$.$2$. Number of terminal $CO$ ligands $(Y)$: In the solid-state structure of $[Co_{2}(CO)_{8}]$,there are $6$ terminal $CO$ ligands (each $Co$ atom is bonded to $3$ terminal $CO$ groups) and $2$ bridging $CO$ ligands. So,$Y = 6$.$3$. Calculation: $X + Y = 1 + 6 = 7$.

In the cobalt-carbonyl complex: $[Co_{2}(CO)_{8}]$,the number of $Co-Co$ bonds is "$X$" and the number of terminal $CO$ ligands is "$Y$". Find the value of $X + Y$.

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