In the condensed schematic representation of | vedclass

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Question

(A) The correct option is $A$. In the Calvin cycle (dark reaction),the process consists of three main stages: $1$. Carboxylation $(A)$: $CO_2$ is fixe

Vedclass · Accepted Answer

$A = CO_2$ fixation,$B =$ Phosphorylation,$C =$ Reduction,$D =$ Regeneration

Vedclass · Answer

(A) The correct option is $A$. In the Calvin cycle (dark reaction),the process consists of three main stages: $1$. Carboxylation $(A)$: $CO_2$ is fixed by $RuBP$ to form an unstable compound which breaks down into $PGA$. $2$. Reduction ($B$ and $C$): This involves two steps: - Phosphorylation $(B)$: $PGA$ is converted to $1,3$-bisphosphoglycerate using $ATP$. - Reduction $(C)$: $1,3$-bisphosphoglycerate is reduced to $G3P$ (or $3-PGA$ aldehyde) using $NADPH$. $3$. Regeneration $(D)$: $RuBP$ is regenerated from $RuMP$ using $ATP$ to continue the cycle.

In the condensed schematic representation of the dark reaction of photosynthesis given below,steps are indicated by alphabets. Select the option where the alphabets are correctly identified.

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