In the conversion $Br_2 \to BrO_3^-$,the oxidation state of bromine changes from

  • A
    $0$ to $-1$
  • B
    $0$ to $+1$
  • C
    $0$ to $+5$
  • D
    $0$ to $+7$

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$2$ mole of $N_2H_4$ loses $16$ mole of electrons and is converted to a new compound $X$. Assuming that all of the $N$ atoms appear in the new compound,what is the oxidation state of $N$ in $X$?

Assign oxidation number to the underlined elements in each of the following species:
$(a)$ $NaH_2\underline{P}O_4$
$(b)$ $NaH\underline{S}O_4$
$(c)$ $H_4\underline{P_2}O_7$
$(d)$ $K_2\underline{Mn}O_4$
$(e)$ $Ca\underline{O_2}$
$(f)$ $Na\underline{B}H_4$
$(g)$ $H_2\underline{S_2}O_7$
$(h)$ $KAl(\underline{S}O_4)_2 \cdot 12H_2O$

Oxidation state of sulphur in tetrathionic acid is

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What is the oxidation number of $S$ in $SO_3^{2-}$?

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