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(D) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$.Since the initial state $i$ and final state $f$ are the same for bot

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$\Delta Q_A > \Delta Q_B$

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(D) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$.Since the initial state $i$ and final state $f$ are the same for both processes,the change in internal energy $\Delta U$ is the same for both processes because internal energy is a state function.In a $P-V$ diagram,the work done $\Delta W$ is equal to the area under the curve.From the figure,the area under curve $A$ is greater than the area under curve $B$,which means $\Delta W_A > \Delta W_B$.Since $\Delta Q = \Delta U + \Delta W$ and $\Delta U$ is constant,$\Delta Q_A > \Delta Q_B$ because $\Delta W_A > \Delta W_B$.

In the given figure,two processes $A$ and $B$ are shown by which a thermodynamic system goes from an initial state $i$ to a final state $f$. If $\Delta Q_A$ and $\Delta Q_B$ are respectively the heats supplied to the systems,then:

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