In the figure shown,$A$ and $B$ are free to move. All the surfaces are smooth. Then for $(0 < \theta < 90^o)$:

The time taken by a block of wood (initially at rest) to slide down a smooth inclined plane $9.8 \ m$ long (angle of inclination is $30^o$) is ......... $sec$.

$A$ frictionless wire $AB$ is fixed on a circle of radius $R$. $A$ very small bead slips on this wire. The time taken by the bead to slip from $A$ to $B$ is:

It is easier to draw up a wooden block along an inclined plane than to haul it vertically,principally because

$A$ body of mass $10 \ kg$ moves a distance of $10 \ m$ with a constant velocity on a smooth inclined plane of angle $\theta = 30^\circ$. Calculate the work done by the force acting on the body in $J$. $[g = 10 \ m/s^2]$

Two inclined frictionless tracks,one gradual and the other steep,meet at $A$ from where two stones are allowed to slide down from rest,one on each track. Will the stones reach the bottom at the same time? Will they reach there with the same speed? Explain. Given $\theta_{1}=30^{\circ}, \theta_{2}=60^{\circ},$ and $h=10 \; m,$ what are the speeds and times taken by the two stones?